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An element occurs in the body centred cubic alttic with cell edge of 300 pm. The density of the element is `8.0 g//cm^(3)`. Answer the following the distance fo closest approach between the two atoms of the element in the lattics isA. 260 pmB. 300 pmC. 600 pmD. 150 pm

Answer» Correct Answer - A
Distance of closest approch in bcc `=(sqrt(3)a)/(2)`
`=(sqrt(3)x300)/(2)=260`


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