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InterviewSolution
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An element (with atomic mass=250 g) crystallises in a simple cube. If the density of unit cell is 7.2 g `cm^(-3)` , what is the radius of the element ?A. `1.93xx10^(-6)` cmB. `1.93xx10^(-8)` cmC. `1.93xx10^(-8) Ã…`D. `1.93 xx 10^(-8)`m |
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Answer» Correct Answer - B `Z=(l^(3)xxrhoxxN_(A))/(M)` `1=(l^(2)xx7.2xx6.023xx10^(23))/(250)` `l=3.86xx10^(-8)` cm `l=2r` (for simple cubic unit cell) `r=(l)/(2)=(3.86xx10^(-8))/(2)=1.93xx10^(-8)` cm |
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