An element with density 11.2 ` g cm^(-3)` forms a f.c.c lattic with edge lengh of ` 4 xx 10^(-8)` cm. calculate the of atoms mass of the element ( Given : ` N_(A) = 6.022 xx 10^(23) mol^(-1)`

An element with density 11.2 ` g cm^(-3)` forms a f.c.c lattic with ed

1.	An element with density 11.2 ` g cm^(-3)` forms a f.c.c lattic with edge lengh of ` 4 xx 10^(-8)` cm. calculate the of atoms mass of the element ( Given : ` N_(A) = 6.022 xx 10^(23) mol^(-1)`
Answer» Correct Answer - `24.12 xx 10^(23) ` atoms `p (Z xx M)/( a^(3)xx N_(A)) ` For element with f.c.c. lattice, Z = 4 ` M = ( p xx a^(3) xx N_(A))/ Z = (( 11.2 " g cm"^(-3)) ( 4xx 10^(-8) "cm")^(3) xx ( 6.022 xx 10^(23) "mol"^(-1)))/4 = 107.9 " g mol"^(-1)`

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An element with density 11.2 ` g cm^(-3)` forms a f.c.c lattic with edge lengh of ` 4 xx 10^(-8)` cm. calculate the of atoms mass of the element ( Given : ` N_(A) = 6.022 xx 10^(23) mol^(-1)`

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