An element with density `11.2 g cm^(-3)` forms a f. c. c. lattice with edge length of `4xx10^(-8)` cm. Calculate the atomic mass of the element. (Given : `N_(A)= 6.022xx10^(23) mol^(-1)`

An element with density `11.2 g cm^(-3)` forms a f. c. c. lattice with

1.	An element with density `11.2 g cm^(-3)` forms a f. c. c. lattice with edge length of `4xx10^(-8)` cm. Calculate the atomic mass of the element. (Given : `N_(A)= 6.022xx10^(23) mol^(-1)`
Answer» Given, Density, `d = 11.2 g cm ^(-3)`, Edge length `a = 4xx 10^(-8) cm,` Avogafro number, `NA = 6.022xx10^(23)` Number of atoms present per unit cell, Z (fcc) = 4 We know for a crystal system = `(ZxxM)/(a^(3) xxNA)` `rArr =(dxxa^(3)xxNa)/(Z) = (11.2xx64xx10^(-24) xx6.022xx10^(23))/(4) = 107.91 g` Thus, atomic mass of the element is `107.91` g.

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