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An element `X (At,wt = 80 g//mol)` having fcc structure, calculate the number of unit cells in `8g of X`A. `0.4xxN_(A)`B. `0.1xxN_(A)`C. `4xxN_(A)`D. None of these |
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Answer» Correct Answer - 4 No. of atoms = 4 Total no. of atoms `=(8)/(80)xxN_(A)` no. of unit cell `=(N_(A))/(10)xx(1)/(4)` `=(6.0)/(4)xx10^(22)` `=1.5xx10^(22)` |
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