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An element X has the following isotopic composition 200X = 90 %, 199X = 8 % and 202X = 2 %. The weighted average atomic mass of the element X is closest to ………… (a) 201 u (b) 202 u (c) 199 u (d) 200 u |
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Answer» (d) 200 u \(=\frac{(200\times90)+(199\times8)+(202\times2)}{100}\) = 199.96 = 200 u |
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