1.

An element `X` has the following istopic compositon: `.^(200)X(90%), .^(199)X(8.0%), .^(202)X(2.0%)` The weighted average atomic mass of the naturally occuring element `X` is closent toA. `202 am u`B. `200 am u`C. `199 am u`D. `201 am u`

Answer» Correct Answer - B
Average atomic mass
= sum total of (Fractional abundance `xx` Isotopic mass)
`= (0.9)(200) + (0.08)(199) + (0.02) (202)`
`= 180 + 15.92 + 4.04`
`= 199.96 ~~ 200`


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