InterviewSolution
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InterviewSolution
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An element X with an atomic mass of 60 g/mol has density of 23 g cmLength of its cubic unit cell is 400 pm, identify the type of cubic unit cell CafRadius of an atom of this element. |
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Answer» we have density d=ZM/a^3NaZ=no of atom to calculateM is the molecular massNa is the avagadro constanta is the edge lengthZ=(d*a^3Na)/M=6.23*(4*10^-8)^3*6*10^23/60=4Therefore th unit cell is FCC.and the length of the unit cell is sqrt2 a=4*radius=sqrt2/4*400pm=141.4pm |
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