An element ZSA decays to 85R222 after emitting 2α particles and If pa

1.	An element ZSA decays to 85R222 after emitting 2α particles and If particle. Find the atomic number and atomic mass of the element S.
Answer» On emission of 2 alpha particles, mass number is reduced by 8 and atomic number by 4. _zS^A → _z-4Q^A-8 + 2 ₂he⁴ Now, on emission of 1 beta particle, mass number remains same but atomic number increases by 1. _z-4Q^A-8 → _z-3Q^A-8 +⁰_-1β After decay, given element is ₈₅R²²².Therefore A-8 = 222 ⇒ A = 230 (Atomic Mass) Z-3 = 85 ⇒ Z = 88 (Atomic No.)

An element ZSA decays to 85R222 after emitting 2α particles and If particle. Find the atomic number and atomic mass of the element S.

Answer»

On emission of 2 alpha particles, mass number is reduced by 8 and atomic number by 4.

_zS^A → _z-4Q^A-8 + 2 ₂he⁴

Now, on emission of 1 beta particle, mass number remains same but atomic number increases by 1.

_z-4Q^A-8 → _z-3Q^A-8 +⁰_-1β

After decay, given element is ₈₅R²²².Therefore

A-8 = 222 ⇒ A = 230

(Atomic Mass)

Z-3 = 85 ⇒ Z = 88

(Atomic No.)