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An elevator ascends with an upward acceleration of 0.2m//s^(2). At the instants its upward speed is 3m//sec a loose bot 5m high from the floor drops from the ceiling of the elevator. Find the time until the bolt strikes the floor and the displacement it has fallen |
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Answer» Solution :Initial VELOCITY of bolt relative to the floor of ELEVATOR = 0 acceleration of bolt relative to the floor of the elevator = `(9.8+0.2)=10ms^(2)` If t is time of the DESCENT then `5=(1)/(2)xx10xxt^(2)` `therefore t=1` SECOND If s is the displacement then `s=-ut+(1)/(2)g t^(2)` `s=-3(1)+(1)/(2)(9.8)(1)^(2) therefore s=1.9m` |
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