An elevator can carry a maximum load of 1800kg (elevator + pasengers) is moving up with a constant speed of 2ms^(-1). The frictional force opposing the motion is 4000N. Determine the minimum power delivered by the motor to the elevator in watts as well as in horse power.

An elevator can carry a maximum load of 1800kg (elevator + pasengers)

1.	An elevator can carry a maximum load of 1800kg (elevator + pasengers) is moving up with a constant speed of 2ms^(-1). The frictional force opposing the motion is 4000N. Determine the minimum power delivered by the motor to the elevator in watts as well as in horse power.
Answer» SOLUTION :The downword force on the elevator is `F= mg + F_(f)= (1800 XX 10) + 4000= 22000N` The motor MUST supply enough power of balance this force. Hence, `P= Fv = 22000 xx 2 = 44000` W= 59 hp