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An elevator with passengers has a total mass of `800 kg` and moves slowly a vertical distance of `20.0 m` in `10.0s`. What is the average power expended in lifting this mass ?A. `1.57xx10^(2) W`B. `1.57xx10^(4) W`C. `1.57xx10^(5) W`D. `1.57xx10^(6) W` |
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Answer» Correct Answer - B Average power`=(mg(Deltah))/(Deltah)` `=(800xx9.8xx20)/(10)=1.57xx10^(4)=1.57xx10^(4)` |
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