1.

An engine operating between 127"^(@)C and 47"^(@)C takes some specified amount of heat from high temperature reservoir. Calculate the percentage efficiency of an engine.

Answer»

Solution :Given :`T_(1)=127"^(@)C=127+273=400 K`
`T_2=47"^(@)C=47+273=320 K`
%efficiency `eta`=?
`eta=[(T_(1)-T_(2))/(T_1)]xx100=[(400-320)/(400)]xx100`
`eta=[(80)/(400)]xx100`
`eta=20%`


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