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An engine operating between `150^(@)C` and `25^(@)C` takes 500 J heat from a higher temperature reservoir if there are no frictional losses, then work done by engine isA. 147.7 JB. 157.75 JC. 165.85 JD. 169.95 J |
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Answer» Correct Answer - A `T_(2)=150+273=423 K , T_(1)=25+273 = 298 K` Q=500 J `(W)/(Q)=(T_(2)-T_(1))/(T_(2)), W=500((423-298)/(423))=147.7 J`. |
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