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InterviewSolution
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An equilateral glass prism has a refrective index 1.6 in air. Calculate the angle of minimum deviation of the prism, when kept in a medium of refractive index `4sqrt2/5`. |
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Answer» `mu=(sin(A+delta_(m)))/(sin-A/2)` `mu=16/((4sqrt2//5))=(1.6xx5)/(4sqrt2), A=60^(@)` `(1.6xx5)/(4sqrt2)=(sin(60+delta_(m)/2))/(sin""60/2)` `(1.6xx5)/(4sqrt2)xx1/2=sin((60+delta_m)/2)` `sin((60+delta_(m))/2)=1/sqrt2` `(60+delta_(m))/2=45^(@)` `60+delta=90^(@)` `delta_(m)=30^(@)` |
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