1.

An equilateral glass prism is made of material of refrative index 1.500. Find its angle of minimum deviation.

Answer»

Solution :`A=60^@,MU=1.5, delta_(MIN)=?`
Substituting in `mu=(sin((A+delta_(min))/2))/sin(A/2)`
`1.5=(sin(60^@+delta_(min))/2)/((sin 60^@/2))`
`1.5 sin 30^@ = sin ((60^@+ delta_(min))/2)`
`sin((60^@+ delta_(min))/2)=1.5 times0.5000=0.7500`
`(60^@+delta_(min))/2=48^@35.`
`60^@+ delta_(min)= 97^@10 implies delta_(min)=37^@.10`


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