1.

An equilateral triangle and a regular hexagon have equal perimeters. The ratio of the area of the triangle and that of the hexagon will be1). 1 : 12). 2 : 33). 3 : 24). 3 : 4

Answer»

Let the side of the EQUILATERAL triangle be ‘X’.

Perimeter of the triangle = 3x

Let the side of the REGULAR hexagon be ‘y’

⇒ Perimeter of regular hexagon = 6y

∴ 6y = 3x

2y = x

y = x/2 ----- (1)

Area of an equilateral triangle = √3x2/4

Area of regular hexagon = 3√3y2/2 = 3√3x2/8 

From (1)

∴ Ratio = (√3x2/4)/(3√3x2/8) = 2 : 3


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