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An equilateral triangle and a regular hexagon have equal perimeters. The ratio of the area of the triangle and that of the hexagon will be1). 1 : 12). 2 : 33). 3 : 24). 3 : 4 |
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Answer» Let the side of the EQUILATERAL triangle be ‘X’. Perimeter of the triangle = 3x Let the side of the REGULAR hexagon be ‘y’ ⇒ Perimeter of regular hexagon = 6y ∴ 6y = 3x 2y = x y = x/2 ----- (1) Area of an equilateral triangle = √3x2/4 Area of regular hexagon = 3√3y2/2 = 3√3x2/8 From (1) ∴ Ratio = (√3x2/4)/(3√3x2/8) = 2 : 3 |
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