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InterviewSolution
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An equilateral tringular loop ADC having some resistance is pulled with a constant velocity v out of a uniform magnetic field directed into the paper. At time t=0, side DC of the loop is at edge of the magnetic field. |
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Answer»
`(AH)/(AE)=(GH)/(EC)` :. `GH=((AH)/(AE))EC` or `GH+((b-VT))/(b).a` `=a-((a)/(b)vt)` :. `FG=2GH=2[a-(a)/(b)vt]` Induced emf, `e=Bv(FG)=2Bv(a-(a)/(b)vt)` :. Induced current `i=(e)/(R )=(2Bv)/(R )[a-(a)/(b)vt]` or `i=k_(1)-k_(2)t` Thus `i-t` graph is a straight line with negative slope and positive intercept. 
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