An equimolar mixture of Na_(2)C_(2)O_(4) and H_(2)C_(2)O_(4) required V_(1)L of 0.1 M KMnO_(4) in acidic medium for complete oxidation. The same amount of the mixture required V_(2)L of 0.1 M NaOH for neutralization. The ratio of V_(1) to V_(2) is

An equimolar mixture of Na_(2)C_(2)O_(4) and H_(2)C_(2)O_(4) required

1.	An equimolar mixture of Na_(2)C_(2)O_(4) and H_(2)C_(2)O_(4) required V_(1)L of 0.1 M KMnO_(4) in acidic medium for complete oxidation. The same amount of the mixture required V_(2)L of 0.1 M NaOH for neutralization. The ratio of V_(1) to V_(2) is
Answer» `1:2` `2:1` `2:5` `5:2` Solution :Let no. of MOLES of `Na_(2)C_(2)O_(4)` & `H_(2)C_(2)O_(4)=a` Eqts of `(Na_(2)C_(2)O_(4))` + Eqts of `H_(2)C_(2)O_(4)` = Eqts of `KMnO_(4)` `(axx2)+(axx2)=0.1xx5xxV_(1)` `4a=0.1xx5V_(1)""…..(1)` Eqts of `(Na_(2)C_(2)O_(4)) +` Eqts of `H_(2)C_(2)O_(4)` = Eqts of NaOH `axx2=0.1xx1xxv_(2)"".....(2)` On solving (1), (2) implies `(V_(1))/(V_(2))=2:5`