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An erect image `3 times` the size of the object is obtained with a concave mirror of radius of curvature `36 cm`. What is the position of the object ? |
Answer» Here, `m = + 3` (because image is erect) `R = -36 cm, u = ? Let u = -x` As `m = (h_2)/(h_1) = (+ v)/(-u) = 3 :. v = -3 u = 3 x` As `(1)/(u)+(1)/(v)=(1)/(f)=(2)/( R) :. (1)/(-x)+(1)/(3x)=(2)/(-36)` `(-3 + 1)/(3x) = - (1)/(18)` or `3x = 36 :. x = 12 cm` `:. u = -12 cm`. |
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