An excess of `AgNO_3` is added to `100mL` of a `0.01M` solution of dichlorotetraaquachromin (III) chloride. The number of moles of `AgCl` precipitated would be:A. (a) `0.002`B. (b) `0.003`C. (c) `0.01`D. (d) `0.001`

An excess of `AgNO_3` is added to `100mL` of a `0.01M` solution of dic

1.	An excess of `AgNO_3` is added to `100mL` of a `0.01M` solution of dichlorotetraaquachromin (III) chloride. The number of moles of `AgCl` precipitated would be:A. (a) `0.002`B. (b) `0.003`C. (c) `0.01`D. (d) `0.001`
Answer» Correct Answer - D `AgNO_3+[Cr(H_2O)_4Cl_2]ClrarrAgCl+[Cr(H_2O)_4Cl_2]NO_3` millimole of `AgNO_3` added is `100xx0.1=1` `:.` Mole of `AgCl=1xx10^-3=0.001` (As `AgNO_3` causes ppt of `AgCl` so `AgCl` ppt is `10^-3` moles.)

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An excess of `AgNO_3` is added to `100mL` of a `0.01M` solution of dichlorotetraaquachromin (III) chloride. The number of moles of `AgCl` precipitated would be:A. (a) `0.002`B. (b) `0.003`C. (c) `0.01`D. (d) `0.001`

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