An excess of `AgNO_(3)` is added to `100mL` of a `0.01M` solution of dichlorotetraaquachromium(III) chloride The number of moles of `AgCI` precipitated would be .A. `0.002`B. `0.003`C. `0.01`D. `0.001`

An excess of `AgNO_(3)` is added to `100mL` of a `0.01M` solution of d

1.	An excess of `AgNO_(3)` is added to `100mL` of a `0.01M` solution of dichlorotetraaquachromium(III) chloride The number of moles of `AgCI` precipitated would be .A. `0.002`B. `0.003`C. `0.01`D. `0.001`
Answer» Correct Answer - D `[Cr(H_(2)O)_(4)C1_(2)]C1 implies 1` mol AgC1 1 mol no of mooles = (Molarity)(Vol. of soln. in litres) `= (0.01 M) (0.1 L)` `= 0.001` Thus, `0.001` mol of complex will yield `0.001` mol of AgC1

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An excess of `AgNO_(3)` is added to `100mL` of a `0.01M` solution of dichlorotetraaquachromium(III) chloride The number of moles of `AgCI` precipitated would be .A. `0.002`B. `0.003`C. `0.01`D. `0.001`

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