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An experiment was set up to determine the percentage of water absorbed by raisins. If the mass of dry raisins was 40 g, and the mass of wet raisins was 45 g, then the percentage of water absorbed would be:A. `(45g)/(40g)xx100`B. `(40g)/(45g)xx100`C. `((45-40)g)/(40g)xx100`D. `((45-40)g)/(45g)xx100` |
| Answer» Correct Answer - C | |