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An explosion breaks a rock into three parts in a horizontal plane two of them go off at right angles to each other the first part of mass 1 kgmoves with a speed of 12 m/sthe second part of mass 2kgmoves with a speedof 8 m/sand thethird aprt flies off with a speed of 4 m/s calculate the mass of third part

Answer»

10 kg
2.5 kg
4 kg
5 kg

Solution :`m_(1) vec(v )_(1)+ m_(2) vec(v )_(2)+ m_(3)v_(3) = 0`
`:. |m_(3) vec(v )_(3) | = |-(m_(1) vec(v )_(1)+ m_(2) vec(v )_(2))|`
`m_(3) v_(3)= SQRT(m_(1)^(2) v_(1)^(2) + m_(2)^(2) v_(2)^(2))`
`4m_(3) = sqrt(144+ 256)= sqrt(400)= 20`
Mas`m_(3)= (20)/(4) = 5kg`


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