An expression, which when divided by (x +1) gives (x2 – x + 1) as qu

1.	An expression, which when divided by (x +1) gives (x2 – x + 1) as quotient and 3 as remainder is equal to :(a) x3 - 2(b) x3 - 1 (c) x3 + 2(d) (x3 + 4)
Answer» (d) (x³ + 4) Dividend = Divisor × Quotient + Remainder = (\(x\) + 1) x (\(x^2 - x+1\)) +3 = \(x\) (\(x^2 - x+1\)) + (\(x^2 - x+1\)) + 3 Now solve.

An expression, which when divided by (x +1) gives (x2 – x + 1) as quotient and 3 as remainder is equal to :(a) x3 - 2(b) x3 - 1 (c) x3 + 2(d) (x3 + 4)

Answer»

(d) (x³ + 4)

Dividend = Divisor × Quotient + Remainder

= (\(x\) + 1) x (\(x^2 - x+1\)) +3

= \(x\) (\(x^2 - x+1\)) + (\(x^2 - x+1\)) + 3

Now solve.