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An fcc lattice has a lattice parameter `a = 400` pm. Calculater the molar volume of the lattice including all the empty space.A. 7.6 mLB. 6.5 mLC. `10.8 ` mLD. 9.6 mL |
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Answer» Correct Answer - D Volume `=a^(3)=(400xx10^(-10)cm)^(3)=64xx10^(-24)cm^(3)` `V_("total")=VN_(A)=64xx10^(-24)xx6.02xx10^(23)=38.4` Molar volume `=(1)/(4)xxV_("total")=(38.4)/(4)=9.6ml`. |
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