1.

An ice box is built of wood of thickness 1.75 cm. The box has an inner lining of cork 2 cm thick. If the difference in temperature between the interior of the box and outside is 12°C, calculate the temperature of the interface between wood and cork. Thermal conductivity of wood and cork are respectively 0.25 and 0.05 in S.I. unit.

Answer»


Solution :`0.25 XX A xx (285 - theta) // 1.75 xx 10^(-2)= 0.05 xx A ( theta - 273)//2 xx 10^(-3) , theta = 283.21` K


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