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An ice cube of mass 0.1 kg of 0^@Cis placed in an isolated container which is 227^@CThe specific heat capacity S of the container varies with temperature T according to the empirical relation S = A+BT, where A = 100 cal/kg -K and B = 2xx10^(2) cal//kg - K^(-2).If the final temperature of the container is 27^@C Latent heat of fusion of water is 8x10^(4) cal/kg, specific heat of water is 10^(-3)cal/kg-k. Heat gained by the ice will be : |
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Answer» `10xx10^(13)` cal |
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