An ice skater spins with arms outstreched at 1.9 rps. Her moment of inertis at this instant is `1,33 kg m^(2)`. She pulls in her arms to increase her rate of spin. If the moment of inertia is `0.48 kg m^(2)` after she pulls in her arms, what is her new rate of rotation?

An ice skater spins with arms outstreched at 1.9 rps. Her moment of in

1.	An ice skater spins with arms outstreched at 1.9 rps. Her moment of inertis at this instant is `1,33 kg m^(2)`. She pulls in her arms to increase her rate of spin. If the moment of inertia is `0.48 kg m^(2)` after she pulls in her arms, what is her new rate of rotation?
Answer» Correct Answer - 5.26 rps

Discussion

No Comment Found

Related InterviewSolutions

A solid cylinder and a sphere, having the same mass, rolls without slipping with the same linear velocity. If the kinetic energy of the cylinder is `75 J`, that of the sphere must beA. `60 J`B. `70 J`C. `80 J`D. `90 J`
The M.I. of solid sphere of mass M and radius R about its diameter isA. `(2)/(5) MR^(2)`B. `(7)/(5)MR^(2)`C. `(2)/(3)MR^(2)`D. `(5)/(3)MR^(2)`
If a solid sphere of mass 500 gram rolls without slipping with a velocity of 20 cm/s, then the rolling kinetic energy of the sphere will beA. 140 JB. 280 JC. 0.014 JD. 0.028 J
If I is the M.I. of a solid sphere about an axis parallel to a diameter of the sphere and at a distance x from it, which of following graphs represents the variation of I with xA. B. C. D.
A disc is rotaing with an angular velocity `omega_(0)`. A constant retarding torque is applied on it to stop the disc. The angular velocity becomes `(omega_(0))/(2)` after n rotations. How many more rotations will it make before coming to rest ?A. nB. 2nC. `(n)/(2)`D. `(n)/(3)`
The M.I. of a solid cylinder about its axis is I. It is allowed to rool down an incline plane without slipping. If its angular velocity at the bottom be `omega`, then kinetic energy of rolling cylinder will beA. `I omega^(2)`B. `(3)/(2)I omega^(2)`C. `2 I omega^(2)`D. `(1)/(2)I omega^(2)`
If a disc of mass 400 gm is rolling on a horizontal surface with uniform speed of 2 m/s, then its rolling kinetic energy will beA. 0.12 JB. 1.2 JC. 120 JD. 12 J
A rigid and a disc of different masses are rotating with the same kinetic energy. If we apply a retarding torque `tau` on the ring, it stops after making n revolution. After how many revolutions will the disc stop, if the retarding torque on it is also `tau` ?A. nB. 2nC. 4nD. n/2
If the torque acting on a system is zero then, which of the followin quantities is conserced ?A. linear momentumB. angular momentumC. moment of inertiaD. angular velocity
The dimensions of torque are :A. `[L^(3)M^(0)T^(-2)]`B. `[L^(2)M^(2)T^(-3)]`C. `[L^(2)M^(1)T^(-2)]`D. `[L^(2)M^(-1)T^(-3)]`

An ice skater spins with arms outstreched at 1.9 rps. Her moment of inertis at this instant is `1,33 kg m^(2)`. She pulls in her arms to increase her rate of spin. If the moment of inertia is `0.48 kg m^(2)` after she pulls in her arms, what is her new rate of rotation?

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment