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An icebox almost completely filled with ice at 0°C is dipped into an area volume of water at 20°C. The box has walls of surface area 2400cm2, thickness 2.0mm and thermal conductivity 0.06W/m-°C. Calculate the rate at which the ice melts in the box. Latent heat of fusion of ice = 3.4 x 105J/kg. |
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Answer» A = 2400cm2 = 2400 × 10–4m2 Q/t = (KA(θ1 - θ2)/l = (0.06 x 2400 x 10-4 x 20)/(2 x 10-3) = 24 x 6 x 10-1 x 10 = 24 x 6 = 144J/sec Rate in which ice melts = m/t = Q/(t x L) = 144/(3.4 x 105)kg/h = (144 x 3600)/(3.4 x 105)kg/s = 1.52kg/s. |
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