An ideal gas at 13^(0)C , is heated to double its volume at constant pressure. Find the final temperature of the gas.

An ideal gas at 13^(0)C , is heated to double its volume at constant p

1.	An ideal gas at 13^(0)C , is heated to double its volume at constant pressure. Find the final temperature of the gas.
Answer» Solution :Initial temperature `t_(1) = 13^(0)` C `T_(1) = 13 + 273 = 286 `K Initial volume `V_(1) = V `, final Volume `V_(2) = 2V` Final temperature `t_(2)` = ? From Charles.law at constant pressure `(V_(1))/(T_(1)) = (V_(2))/(T_(2)) rArr T_(2) = (V_(2))/(V_(1)) T_(1) = (2V)/(V) XX 286 = ` 572 k Final temperature, `t_(2) = 572 - 273 = 299^(0)` C