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An ideal gas at 13^(@)C, is heated to double its volume at constant pressure. Find the final temperature of the gas. |
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Answer» Solution :Initial temperature `t_(1)=13^(@)C,T_(1)=13+273=286K,` Initial VOLUME `V_(1)=V` Final volume `V_(2)=2V` , Final temperature `t_(2)=?` From Charles. law at constant pressure `rArr V_(1)/T_(1)=V_(2)/T_(2) rArr T_(2)=V_(2)/V_(1)T_(1)=(2V)/V times 286=572K` Final temperature, `t_(2)=572-273=299^(@)C` |
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