InterviewSolution
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InterviewSolution
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An ideal gas has a specific heat at constant pressure `C_P=(5R)/2`. The gas is kept in a closed vessel of volume `0.0083m^3`, at a temperature of 300K and a pressure of `1.6xx10^6 N//m^2`. An amount of `2.49xx10^4` Joules of heat energy is supplied to the gas. Calculate the final temperature and pressure of the gas. |
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Answer» As here volume of gas remains constant, we have `(Delta Q)_(v) = mu C_(v) Delta T` Here, `C_(v) = C_(P) - R (5//2) R - R = (3//2) R` `mu = (PV)/(RT) = (1.5 xx 10^(6) xx 8.3 xx 10^(-3))/(8.3 xx 300) = (16)/(3)` `2.49 xx 10^(4) = (16)/(3) xx (3)/(2) xx 8.3 Delta T` i.e., `Delta T = 375` or `T_(2) - T_(1) = 375`, i.e., `T_(2) = (375 + 300)` Now as for a given mass of an ideal gas at constant volume, `P prop T` `(P_(2)// P_(1)) = (T_(1) // T_(2))` `P_(2) = (675)/(300) xx 1.6 xx 10^(6) = 3.6 xx 10^(6) N//m^(2)` |
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