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An ideal gas hea engine operates in a Carnot cycle between 227^(@)C and 127^(@)C. It absorbs 6 kcal of heat at higher temperature. The amount of heat in kcal rejected to sink is |
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Answer» 4.8 `T_(2) = 127^(@)C = 127 + 273 = 400 K, Q_(1) = 6 KCAL` As `(Q_(2))/(Q_(1)) = (T_(2))/(T_(1)) :. (Q_(2)) = (T_(2))/(T_(1))Q_(1) = (400 K)/(500 K) XX 6 kcal = 4.8 kcal` |
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