1.

An ideal gas is expanded so that amount of heat given is equal to the decrease in internal energy. The gas undergoes the process TV^(1//5)= constant. The adiabatic compressibility of gas when pressure is P, is -

Answer»

<P>`(7)/(5P)`
`(5)/(7P)`
`(2)/(5P)`
`(7)/(3P)`

Solution :`dQ= -dU`
`C= -C_(V) = (-R)/(gamma-1)=(+R)/(gamma-1)+(P)/(n) (dV)/(dT)`
`-(P)/(n) (dV)/(dT)= (2R)/(gamma-1)`
`T^(5)V=` CONST.
`V=("const.")/(T^(5))`
`(dV)/(dT)= -5("const")/(T^(6))`
`PV=nRT`
`P//n=RT//V`
`+ (RT)/("const.")T^(5) xx (-5 ("const")/(T^(6)))=(2R)/(gamma-1)`
`(5)/(2)=(1)/(gamma-1) rArr gamma-1 =2//5`
`gamma=7//5`
adiabatic compressibility
`beta=(1)/(gammaP)=(5)/(7P)`


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