An ideal gas is initially at a temperature T and volume V. Its volume

1.	An ideal gas is initially at a temperature T and volume V. Its volume is increased by ΔV due to an increase in temperature ΔT, pressure remaining constant. The quantity δ = ΔT/VΔT varies with temperature as
Answer» Correct Option (c) Explanation: From ideal gas equation PV = RT .....(i) or PΔV = RΔT ......(ii) Dividing equation (ii) by (i) we get ΔV/V = ΔT/T = ΔV/VΔT = 1/T = δ :. δ = 1/t. So the graph between δ and T will be rectangular hyperbola.

An ideal gas is initially at a temperature T and volume V. Its volume is increased by ΔV due to an increase in temperature ΔT, pressure remaining constant. The quantity δ = ΔT/VΔT varies with temperature as

Answer»

Correct Option (c)

Explanation:

From ideal gas equation PV = RT .....(i)

or PΔV = RΔT ......(ii)

Dividing equation (ii) by (i) we get ΔV/V = ΔT/T = ΔV/VΔT = 1/T = δ

:. δ = 1/t. So the graph between δ and T will be rectangular hyperbola.