An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature asA. B. C. D.

An ideal gas is initially at temperature T and volume V. Its volume is

1.	An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature asA. B. C. D.
Answer» Correct Answer - C We know that `V//T=`constant `(V+DeltaV)/(T+DeltaT)=(V)/(T)` or `VT=TDeltaV=VT+VDeltaT` or `TDeltaV=VDeltaT` or `(DeltaV)/(VDeltaT)=(1)/(T)` This is representeed by graph.

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An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature asA. B. C. D.

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