An ideal gas is taken through the cycle A → B → C → A, as

1.	An ideal gas is taken through the cycle A → B → C → A, as shown in the figure. If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process C → A is (a) -5 J (b) -10 J (c) -15 J (d) -20 J
Answer» Correct Answer is: (a) -5 J From the first law of thermodynamics, Q = ΔU + W. For a cyclic process, ΔU = 0. Also, ϕ = 5 J W = W_AB + W_BC + W_CA. W_AB = pΔV = (10 N m^-2) \|(1 m³) = 10 J and W_BC = 0. ∴ 5 J = 10 J + W_CA or W_CA + -5 J .

An ideal gas is taken through the cycle A → B → C → A, as shown in the figure. If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process C → A is (a) -5 J (b) -10 J (c) -15 J (d) -20 J

Answer»

Correct Answer is: (a) -5 J

From the first law of thermodynamics, Q = ΔU + W. For a cyclic process, ΔU = 0. Also, ϕ = 5 J

W = W_AB + W_BC + W_CA.

W_AB = pΔV = (10 N m^-2) |(1 m³) = 10 J and W_BC = 0.

∴ 5 J = 10 J + W_CA

or W_CA + -5 J .

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An ideal gas is taken through the cycle A → B → C → A, as shown in the figure. If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process C → A is (a) -5 J (b) -10 J (c) -15 J (d) -20 J

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