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An ideal gas is trapped between a mercury columnand the closed lower end of a narrow vertical tube of uniform bore. The upper end of the tube is open to the atmosphere. (Atmospheric pressure is 76 cm of mercury). The length of the mercury and the trapped gas columns are 20 cm and 43 cm, respectively. What will be the length of the gas column when the tube is tilted slowly in a vertical plane through an angle of 60^(@). Assume the temperature to be constant. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :Boyle.s law <a href="https://interviewquestions.tuteehub.com/tag/holds-1028346" style="font-weight:bold;" target="_blank" title="Click to know more about HOLDS">HOLDS</a> <a href="https://interviewquestions.tuteehub.com/tag/good-1009017" style="font-weight:bold;" target="_blank" title="Click to know more about GOOD">GOOD</a> because the <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> is constant. <br/> So, `P_(1)V_(1)=P_(2)V_(2)" or "P_(1)l_(1)=P_(2)l_(2)` , since the bore is uniform <br/> `P_(1)=76+20=96 cm` of Hg , <br/> `l_(1)=43 cm, P_(2)=76+h=76+20cos60^(@)=76+10=86cm` of Hg <br/> `l_(2)=?` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> 96 times 43=86l_(2)` <br/> `therefore l_(2)=48cm` of Hg</body></html> | |