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An ideal gas undergoes a cyclic process, in which one process is isochoric, one process is isothermal and one process is adiabatic. During the isothermal process, 40 J heat is released by the gas, and during the isochoric process, 80 J heat is absorbed by the gas. if work done by the gas during adiabatic process is `W_(1)` and during isothermal process is `W_(2)` then the magnitude of `(W_(1))/(W_(2))` will be equal to: |
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Answer» Correct Answer - B For isothermal process `W_(2)=Q_(BC)=-40J` for complete cycle `Q_("cycle")=W_("cycle")` `-40+80+0=-40+0+W` `W_(1)=80J` |
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