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An ideal gas whose adiabatic exponent `(gamma)` equal 1.5, expands so that the amount of heat transferred to it is equal to the decrease in its internal energy. Find the `T - V` equation for the processA. `TV =` constantB. `TV^(1//4) =` constantC. `T^(1//4)V =` constantD. `TV^(1//4) =` constant |
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Answer» Correct Answer - B `2 dQ = dW` `rArr -2C_(v) dT = pdV` `rArr (-2R)/(gamma - 1) dT = pdV` `rArr (2R)/(gamma - 1) dT + (RT)/(V) = 0` `TV^((gamma - 1)//2)=` constant |
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