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An ideal gas with density `6 gm//L` has a pressure of 38 torr at room temperature, then calculate the value of root mean square speed (in m/sec) of molecules of this gas. [Take 1 atm `= 10^(5)` Pascal] [Divide your answer by 10] |
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Answer» Correct Answer - 5 `U_("rms") = sqrt((3RT)/(M)) = sqrt((3P)/(d)) = sqrt((3 xx 38 xx 10^(5))/(760 xx 6)) = sqrt((10^(4))/(4))` where `d = 6 gm//"lit". = 6 xx 10^(-3) kg//10^(-3) m^(3) = 6 kg//m^(3)` `U_("rms") = (100)/(2) = 50 m//sec` `= (50)/(10) = 5` |
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