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An ideal liquid is flowing in a cylindrical tube of internal diameter 4 cm with a velocity of 5 ms^(-1). If this tube is connected to another tube of internal diameter 2 cm, then the velocity of the liquid in the second tube will be ? |
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Answer» Solution :According to the equation of continuity `a_2v_2 = a_1v_1 , d_2^2 v_2 = d_1^2v_1` `v_2 = ((d_1)/(d_2))^(2) xx v_1 = (4/2)^2 xx 5` `v_2 = 20 MS^(-1)`. |
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