An ideal spring with spring - constant `K` is bung from the colling and `a` block of mass `M` is attached to its lower end the mass is released with the spring initally unstetched . Then the maximum exlemsion in the spring isA. `(4 Mg)/(k)`B. `(2Mg)/(k)`C. `(Mg)/(k)`D. `(Mg)/(2k)`

An ideal spring with spring - constant `K` is bung from the colling an

1.	An ideal spring with spring - constant `K` is bung from the colling and `a` block of mass `M` is attached to its lower end the mass is released with the spring initally unstetched . Then the maximum exlemsion in the spring isA. `(4 Mg)/(k)`B. `(2Mg)/(k)`C. `(Mg)/(k)`D. `(Mg)/(2k)`
Answer» Correct Answer - B Loss in `P.E` = Gain in `K.E + P.E` stored in spring `MgX_(max) =0+(1)/(2)kX_(max)^(2) , X_(max)=(2Mg)/(k)`.

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An ideal spring with spring - constant `K` is bung from the colling and `a` block of mass `M` is attached to its lower end the mass is released with the spring initally unstetched . Then the maximum exlemsion in the spring isA. `(4 Mg)/(k)`B. `(2Mg)/(k)`C. `(Mg)/(k)`D. `(Mg)/(2k)`

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