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An impedance coil takes 25 A when connected across 220-volt 25-Hz mains and 5.4 A from a 110-V, 60-Hz mains. What is the inductance? |
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Answer» XL=wL L= XL/w(frequency) L=220/(25x25) L=0.3 We know that XL = wL Where, w = frequency L = inductance Then \(L = \frac{X_L}{w}\) \(L = \frac v{iw}\) L = \(\frac{220}{25\times25}\) L = 0.3 H |
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