An impure sample of sodium chloride which weighed 1.2 g gave on treatment with excess of silver nitrate solution 2.4g of silver chloride as precipitate.Calculate the percentage purity of the sample

An impure sample of sodium chloride which weighed 1.2 g gave on treatm

1.	An impure sample of sodium chloride which weighed 1.2 g gave on treatment with excess of silver nitrate solution 2.4g of silver chloride as precipitate.Calculate the percentage purity of the sample
Answer» <html><body><p></p>Solution :The double <a href="https://interviewquestions.tuteehub.com/tag/decomposition-946042" style="font-weight:bold;" target="_blank" title="Click to know more about DECOMPOSITION">DECOMPOSITION</a> reaction involved is: <br/> `NaCl(aq) + AgNO_(3)(aq) to NaNO_(3)(aq) + AgCl(s)` <br/> Mass of NaCl taken = 0.989 g Mass of AgCl formed = 2.42 g <br/> Using the relation <br/> `("Mass of NaCl")/("Mass of AgCl") = ("<a href="https://interviewquestions.tuteehub.com/tag/equivalent-446407" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIVALENT">EQUIVALENT</a> <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of NaCl")/("Equivalent weight of AgCl") =("Eq. weight of Na + Eq. weight of Cl")/("Eq. weight of Ag + Eq. weight of Cl")` <br/> and substituting the values, we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> <br/> `0.989/2.42 = ("Eq. mass of Na" + 35.5)/(108 + 35.5)` <br/> `=(0.989/2.43 xx 143.5) - 35.5 = 58.4- 35.5 = 22.9`</body></html>