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An increase in intensity level of 1 dB implies an increase in intensity of (given anti `log_(10)0.1=1.2589`)A. `1%`B. `3.01%`C. `26%`D. `0.1%` |
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Answer» Correct Answer - C Intensity level is decibel is given by `L=10log_(10)((I)/(I_0))` `L+1=10log_(10)((I_1)/(I_0))` Subtracting, `1=10log_(10)((I_1)/(I_0))-10log_(10)((I)/(I_0))` or `(1)/(10)=log_(10)((I_1)/(I))` or `0.1=log_(10)((I_1)/(I))` or `(I_1)/(I)=1.26` |
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