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An indcutor having self inductance L with its coil resistance R is connected across a battery of emf `elipson`. When the circuit is in steady state t = 0, an iron rod is inserted into the inductor due to which its inductance becomes nL (ngt1). When again circuit is in steady state, the current in it isA. `I lt epsilon//R`B. `I gt epsilon//R`C. `I = epsilon//R`D. None of these |
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Answer» Correct Answer - C When inductance of coil is changed abruptly, flux it remains same. i.e. `phi=LI=constant`. Since here incuctance will increase on insertion of iron rod, so current will decrease. Now current will increases to attain the steady state value `(E//R)`. During thsi time, inductance (nL) will remain same and p.d. across A and B will also remain same. But as current will change with time so rate of prodution of heat will vary. |
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