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InterviewSolution
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An inductor of `2` henry and a resistance of `10` ohms are connected in series with a battery of `5` volts. The initial rate of change of current isA. `0.5amp//sec`B. `2.0amp//sec`C. `2.5amp//sec`D. `0.25amp//sec` |
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Answer» Correct Answer - C `i=(E)/(R)(1-e(-Rt//L)` `(di)/(dt)=(E)/(R)e^(-(Rt)/(L)).(R)/(L)=(E)/(L)e^(-(Rt)/(L))` `t=0, (di)/(dt)=(E)/(L)=(5)/(2)=2.5A//sec` |
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