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An inductor-resistance -battery circuit is switched on at t = 0. If the emf of the battery in one time constant `tau`.A. `(E)/(R)*(tau)/(e)`B. `(E)/(R)*(tau)/(e-1)`C. `(E)/(R)*(tau)/(e+1)`D. `(E)/(R)*(e-1)/(tau)` |
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Answer» Correct Answer - A Current at time t is given by `i=i_(0)(1-e^(-t//(tau)))where (i_0)=E//R` The charge passed through the bettery during the period t to t+dt is idt. The total charge passed during time 0 to `tau` is `Q=int_(0)^(tau) idt = i_(0)i int_(0)^(tau) (1-e^(-t//tau))dt` `=i_(0)[t+(e^(-t//tau))/(tau)]_(0)^(tau) =i_(0)` |
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